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VOLT LAB / 37

Inductor energyJ

Inputs

Inductance · l mH0 … 1,000,000,000 mHCurrent · i A0 … 1,000,000,000 A

Inputs

Inductance · l = 100 mH

Current · i = 2 A

Results

Energy · E: 0.2 J

Formula

E = ½LI²

Model and assumptions

Ideal components; the formula applies only to the circuit and quantities shown. Component tolerances and extra loads are excluded.

Worked example

Inputs

Inductance · l = 100 mH

Current · i = 2 A

Results

Energy · E: 0.2 J

Explore the relationship

ParameterResults

Related tools

Three-phase power

I = P / (√3 × U × cos φ)

RLC impedance

Z = √(R² + (Xᴸ − Xᶜ)²)

Capacitor

Xᶜ = 1/(2πfC) · E = ½CU²

Frequency and period

T = 1/f · ω = 2πf

VOLT LAB · Svenska

Calculations use simplified models. Installations require verified data and checks under local rules.